the working is a little . and hard to type out
lol,
but the correct answers are
1) 9.423 m/s^2
2) 16.593 m/s
for the second one you have to:
differentiate equation – (1)
substitute y= 11 into the equation to get x
substitute the x you found above into (1) – (2)
tan theta = (2)
it’s all angle work, similar triangles and stuff in between
here.
eventually you take a small angle away from a big angle to get the
angle with the velocity (the gradient at y = 11)
cos (angle with velocity) = (r x theta dot) / v
theta dot is your rev/min converted to rad/sec
r is found by using trig
