ispyyy SG lol... try ah...Input Voltage= 240( sin 2*pi*50 + jcos 2*pi*50)= 240( -0.26 +j0.96)= -62.4 +j230.4Total input impedence= 1/(1/z1 + 1/z2 + 1/z3)=2.33+j1.1Total current= Total voltage/Total impedence= 16.27+j91.2Total input power=| Re {VI} |= 22028Total reactant power= | Img {VI} | = 1941 jwC + 1/Zin = Re numberHence,if 1/Zin = 0.35-j0.17,jwC = j0.17C = 5.4x 10E-4 F
ispyyy SG I forgot on the power fomular...Dont noe it is the real number of whole answer or real number x real number....hahaahaha...Check it out yrself lor...:p
ispyyy SG die.i got different values leh.hahaha chui liao la me who noes???u maybe correct lor...I long long long long long time never do this type of question liao... :p
ChoCoChips SG eh and hor,why input voltage ish got the cos and sin one?i tot it's just 240v and 0 degrees only?
ispyyy SG eh and hor,why input voltage ish got the cos and sin one?i tot it's just 240v and 0 degrees only?oh ya hor... me mess up liao...hahahaaa... it is 240V with 0 degrees...:p
