bonkysleuth SG If log2 (y + 1) =2 log2 x+c and y=3 when x=2, find y in terms of x. There seems to be a little problem with this question. Can someone help? I'm not sure what's the 'c' for. and the '2' after each log is the subscript. thanks.
tanjun SG log2 (y+1) = 2log2 (x+c)when y = 3, x = 2log2 (4) = 2log2 (2+c)2 = 2log2 (2+c)log2 (2+c) = 12 + c = 2c = 0 log2 (y+1) = 2log2 (x)
798 SG log2 (y+1) = 2log2 (x+c)when y = 3, x = 2log2 (4) = 2log2 (2+c)2 = 2log2 (2+c)log2 (2+c) = 12 + c = 2c = 0 log2 (y+1) = 2log2 (x)
