gobez14 SG hi can any1 tell mi wads teh answer of 3 log a (2) - 4 + log a (a to the power of 3) whe nconverted into a single logarithmic form and value of x when 4 (x to the power of half) = 3-7x
^tamago^ SG 3 log(a,2) - 4 + log(a,a³) = log(a,8) - log(a,a^4) + log(a,a³) = log[a,(8/a)] 4*sqrt(x)=3-7x Let z be sqrt(x), z>=0 7z²+4z-3=0 (7z-3)(z+1)=0 z = 3/7 or -1 (rej. as z>=0) x = sqrt(3/7)
wishboy SG 4x^½ = 3 - 7x Let x^½ be u 4u = 3 - 7u² 7u² + 4u - 3 = 0 (7u - 3)(u + 1) = 0 7u - 3 = 0 or u + 1 = 0 u = 3/7 or u = -1 x^½ = 3/7 or x^½ = -1 x = 9/49 or 1 FYI, x^½ is equals to "square root of x", written as "sqrt x"
gobez14 SG but hor y i sub 1 into the original equation 1 side is 4 the other side is -4 ? liddat still can??
SBS261P SG x cannot be 1 becoz x^1/2 = -1 means square root x = -1 but square root cannot give negative number so must reject
