eagle SG t^2 + 5t = 0 t(t+5) = 0 t = 0 or t = -5 Do not cancel the t away or you will lose a solution Regards, Eagle
wishboy SG factorise out the t in the equation t² + 5t = 0 t² = t * t 5t = 5 * t * = multiply both got t so can "take it out" which means factorise out the t so... t² + 5t = 0 t * (t + 5) = 0 therefore, t = 0 or t + 5 = 0 t = 0 or -5
yiha093 SG okie next question i have a rectangle 3x-y 3y+4 |----------------- | | | 2x-3 |------------------| 2x+y based on wad i c 3x-y=2x+y 2x-3=3y+4 (stuck le) Find X and Y ?? any1 noes?
yuko-ogura SG 3x-y=2x+y Let x=2y---------------(1) and (2): 2x-3=3y+4 Sub (1) into (2): 2x-3=3y+4 2(2y)-3=3y+4 4y-3y=7 thus y=7 and x=14
gLc SG im not sure how to do. But here goes. Since.. 3x-y=2x+y 2x-3=3y+4 Thus--> 2x = 3x-2y -x=-2y x=2y 2x=3y+4+3 2x=3y+7 2(2y)=3y+7 4y=3y+7 4y-3y=7 So, Y = 7. 3x-(7)=2x+7 3x-2x=7+7 x=14 So Y = 7, X = 14. I think..
^tamago^ SG Originally posted by gLc: im not sure how to do. But here goes. Since.. 3x-y=2x+y 2x-3=3y+4 Thus--> 2x = 3x-2y -x=-2y x=2y ....
