Math - Trigonometry

Darkness_hacker99 SG

I am stuck at this question. Can anyone help me please. Thanks. Smile

The answer provided is 118.4 degree.

stellazio SG

u cna find angle ADB and BDC right using some formula?

kalangkabo SG

eh... your qn put 35 degrees, but your diagram show 33 degrees?

what standard? got learn before |A|/sinA = |B|/sinB = |C|/sinC or not?

Darkness_hacker99 SG

Yes for Angle ADB. No for Angle BDC, the info are not enough.

Darkness_hacker99 SG

opps typo.

Oh ya.. Use sin rule to find.

Now then I saw it. Embarassed

Thx kalangkabo

dbowie SG

sorry calculator spoilt, all i can tell you is ADB is sin-1 0.44

Darkness_hacker99 SG

Embarassed

dbowie SG

hey darky pls elaborate on how to do.. quite interested to know as I am quite stupid .. Razz

Darkness_hacker99 SG

Nah.. You're not stupid. Smile

Dunno why today I quite blur.. Neutral

Darkness_hacker99 SG

I want to thank everybody for help me this question. Thanks ya.. Mr. Green Embarassed

dbowie SG

I didn't notice the CAD Embarassed

Darkness_hacker99 SG

Yar.. Yesterday I also didn't notice. Neutral

eagle SG

I just come online only, and all the questions solved liao… Good good good… save my brain cells for other things =D

Darkness_hacker99 SG

Very Happy

lpx88 SG

*Edit*Wait i got it

Actually got another method.Use a simple sine rule will do it

22 / sin CAD = 25 / sin 33

CAD=sin-1 22 / (25/sin 33)

=28.6 degrees

ADC= 180 degrees - 23.6 degrees - 33 degrees = 118.4 degrees

Darkness_hacker99 SG

But 180 - 45.9 - 33 = 101.1

lpx88 SG

Sry damn tired just now...Careless...Ans revised Very Happy