physics (pressure)

starmoonsun SG

on a particular day, the atmospheric pressure at sea level was 102 000 Nm^2. at the same time, a mercury barometer placed at the top of the mountain indicated 0.6m Hg. Assume that the acceleration due to gravity remained constant. (density of mercury = 13 600kg m^-3)

If the density of the air between the top of the mountain and the sea level is 1.2 kg m^-3, determine the height of the mountain top above sea level

ans is 1700m, but i dunno how to do... anyone can help?

dbowie SG

Pa at mountain = 0.6x10x13600 = 81600
Pa at sea level = 102000 Pa
102000-81600=20400Pa
20400/1.2x10xh
h=1700m.

I hope this solves your question.

unclebutcher SG

Pressure at mountain top=(density)(G)(height)
=13,600*9.81*0.6
=80049.6Pa(Nm-2)

102000-80049.6=(density of air)(G)(height of mountain)
= 1864m

my ans diff cuz i use 9,81 as G, sorry.