MyPillowTalks SG wad is the equation of the line tht passes through the point (1,1) and ish parallel to the line y=-2x+2?
FireIce SG dunno u do differentiation liao not, but nehmind lah straight line eqn: y = mx + c y = -2x + 2 => gradient = m = -2 eqn of line: y = mx + c sub (1,1) into eqn 1 = (-2)(1) + c c = 3 eqn of line: y = -2x + 3 pls transfer $5 to my acct, thank u
