[quote]Originally posted by TYING:
[b]
let y= - 1/2 + 1.5x be eqn 3
[(x-2)(x-2) + (2y+3)(2y+3)] = 26
[(x-2)(square) + (2y+3)(square)] =
26
[(2y+3)(sq.) - (x-2)(sq.)] = -26
sub y in.
[2(-0.5+1.5x) + 3](sq) - (x-2)(sq) = -26
[(-1 + 3x) + 3](sq) - (x-2)(sq) = -26
(2+3x)(sq) - (x-2)(sq) = -26
(2+3x+x-2)(2+3x-x+2) = -26
(4x)(4+2x) = -26
(2x)(2+x) = -13
2x(sq) + 4x + 13 = 0
solve x den find y.
