if you are trying to integrate sin(x)^5,
you can break it into sin(x)^4*sin(x),
= (sin(x)^2)^2 * sin(x)
= (1-cos(x)^2)^2 *sin(x)
let u=cos(x), notice that du becomes -sin(x).
So you whole expression becomes
- Intergate {(1-u^2)^2 du}
= - Integare {(1-2u^2+u^4) du}
hi sorry think i am not answering your question
