jenn_y SG it is. the qn is just asking u to prove that left hand = right hand. doesn't matter 0=0 or 1=1 or -1=-1 btw nicely done whoever solved this.
^tamago^ SG 1) For any real number x: x² - x² + x = x² - x² + x 2) Factoring both sides in two different ways: x² + x² - x² - x² + x = x² - x² + x (x - x)(x + x) + x = x(x - x) + x 3) Dividing both sides by (x - x): (x + x) + [x/(x - x)] = x + [x/(x - x)] 4) Minus both sides by [x/(x - x)]: x + x = x 2x = x 5) Since this is valid for any value of x, we can plug in x = 1. 2 = 1
dcx SG prove? lagi easier.... i've 1 apple and mary has 1 apple. I ate 1 apple and mary ate 1apple...how many apples left? 1 - 1 = 1 - 1 0 = 0
Gasfene SG This is in my opinion number theory. If number theory dont deal with it, then its to do with Mathematical Logic. All these rules will be applied when you use algebra.
ch0i SG aiyo 1 ask me balik kampong one say i bad person no no ch0i bely bely gud u noee oni ch0i duno maths not duno lar ch0i has fobia of maths
