borntolive SG i tink square root P and A then bring square root of A over to square root of P n i tink u can proceed.. not very sure wait for others to give u ans..
ndmmxiaomayi SG p = a(m - b)^2 p/a = (m - b)^2 square root (p/a) = square root (m - b)^2 square root (p/a) = m - b square root (p/a) + b = m
dragg SG try for fun p = a(M2 - b2) p = aM2 - ab2 p/a = M2 - b2 p/a + b2 = M2 square root of p/a + b = M is it correct?
CoolMyth SG P = a(M - b)^2 P/a = (M - b)^2 --> (+-)sqr(P/a) = M - b --> M = [(+-)(sqr)P/a] + b Now promoting my "maths forum" http://www.sgforums.com/?action=thread_display&thread_id=161403 EDIT: careless.
